5x^2-2x-0.0125=0

Solution for 5x^2-2x-0.0125=0 equation:

5x^2-2x-0.0125=0

a = 5; b = -2; c = -0.0125;
Δ = b2-4ac
Δ = -22-4·5·(-0.0125)
Δ = 4.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{4.25}}{2*5}=\frac{2-\sqrt{4.25}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{4.25}}{2*5}=\frac{2+\sqrt{4.25}}{10}
$